Primitive Archer
Main Discussion Area => Bows => Topic started by: Cloudfeather on February 07, 2013, 09:32:18 pm
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I'm thinking of doing a five curve, sinew backed Osage as my next project. Any tips on some dimensions? I'm shooting for about a 58" ntn length and a draw weight of about #70 @ 26". Any info or tips would be appreciated.
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I got Gun Doc's Prairie Rattler in last year's bow trade. It is a osage sinew backed 5 curve that pulls 70# at 26". I believe it's a little shorter than your plan but I could give you the measurements from it any way as a guide. I'd ask Gun Doc if you have any more questions about it. It's a sweet bow, for sure. It is 54" long and it is about 1 3/4" at the fades tapering smoothly to about 3/8" at the tips. Hope that's helpful. Good luck.
here's a link to his bow. http://www.primitivearcher.com/smf/index.php/topic,33345.msg439926.html#msg439926
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Thanks, I'll take that into consideration. I'm sure some of the other Osage fanatics will chime in as well. lol. I'm thinking of a very slight molly type static tip but with a very subtle curve to it. If that makes any sense. :P
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Can't wait to see some pics, I love the profile on a 5 curve.
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You could do it 1" wide its full length or maybe 1 1/4" with the handle area reduced to 1".
I've never made a 5 curve bow but it doesn't take much osage to make a bow and even less if you add sinew. ;)
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Ive made a few of these. if you want to keep some reflex in it or most of it make it 1.5 inches wide.
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Any tips on how to go about setting back the handle? I was thinking about making a small jig and using this one huge c clamp I have with a combo of steam and heat gun.